Why Can't We Integrate e^(x^2) Using Elementary Functions?

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Homework Statement



integrate e(x2)

Homework Equations





The Attempt at a Solution



e(x2) = (ex)2

substitute (ex) = u so (ex)dx = du

therefore

∫e(x2) dx = ∫u du

Unfortunately this is not the correct answer
Can someone please tell me what I am doing wrong?

Thanks
 
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Do you know the Taylor expansion of ##e^x##?
 
The first line of your attempt is where you went wrong. e^{(x^{2})}\neq (e^{x})^{2}. Rather, (e^{x})^{2}=e^{x}e^{x}=e^{2x}

Otherwise, I kind of suck at this kind of problem. I never remembered all the fun rules, so I would go the really long route:
e^{(x^{2})}=1+x^{2}+x^{4}/2+x^{6}/6+x^{8}/24+x^{10}/120+...
so the integral would be
x+x^{3}/3+x^{5}/10+x^{7}/42+x^{9}/216+x^{11}/1320+...

From there, I guess good luck?
 
kmr159 said:

Homework Statement



integrate e(x2)

Homework Equations





The Attempt at a Solution



e(x2) = (ex)2

substitute (ex) = u so (ex)dx = du

therefore

∫e(x2) dx = ∫u du

Unfortunately this is not the correct answer
Can someone please tell me what I am doing wrong?

Thanks

You can only express the integral of ##e^{(x^2)}## in term of nonelementary functions like the error function 'erf'. http://en.wikipedia.org/wiki/Error_function Is that what you are expected to do?
 
kmr159 said:

Homework Statement



integrate e(x2)

Homework Equations





The Attempt at a Solution



e(x2) = (ex)2

substitute (ex) = u so (ex)dx = du

therefore

∫e(x2) dx = ∫u du

Unfortunately this is not the correct answer
Can someone please tell me what I am doing wrong?

Thanks

To expand on Dick's answer: it has been rigorously shown that it is impossible to express the indefinite integral of ##\exp(x^2)## in terms of a finite number of elementary functions. It is not just that nobody has been smart enough to figure out how to do it; it is proven that is it impossible for anybody to do, ever. Even if you write trillions of terms on a piece of paper as large as the solar system you still cannot write out the result exactly. Of course, you can express the result in non-finite terms, such as through an infinite series, etc.
 
Ray Vickson said:
To expand on Dick's answer: it has been rigorously shown that it is impossible to express the indefinite integral of ##\exp(x^2)## in terms of a finite number of elementary functions. It is not just that nobody has been smart enough to figure out how to do it; it is proven that is it impossible for anybody to do, ever. Even if you write trillions of terms on a piece of paper as large as the solar system you still cannot write out the result exactly. Of course, you can express the result in non-finite terms, such as through an infinite series, etc.

Nice expansion, Ray Vickson. I was just interested in what was expected. But that gave it more depth.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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