Why do Balloons filled with Air not fall at 9.6m/s/s?

  • Thread starter Thread starter Salbris
  • Start date Start date
  • Tags Tags
    Air Fall
AI Thread Summary
Balloons filled with air do not fall at the expected rate due to the properties of buoyancy and terminal velocity. When a balloon is inflated with breath, it contains a gas mixture similar to the surrounding air, with only a slight increase in carbon dioxide. The weight difference is minimal, and the large surface area of the balloon contributes to a low terminal velocity, causing it to descend slowly. This means that the buoyancy effect is not solely dependent on the gas being lighter than the surrounding air. Understanding these principles clarifies why the balloon behaves as it does in the atmosphere.
Salbris
Messages
29
Reaction score
0
I've been racking my brain to figure this one out, I really don't understand it.

If you fill a balloon with air from your lungs, just manually blow it up, it should be carbon dioxide, no?

Density of Carbon Dioxide at Sea Level: 1.977 g/L
Density of Air at Sea Level: 1.2 g/L

So it's heavier. I know I'm pulling these numbers out of seemingly nowhere, but I'm sure someone can verify they are accurate.


So why on Earth would a balloon filled with a gas heavier than the surrounding gas in it's environment not drop at the normal speed. Aren't I right to think that bouyancy only takes effect when the gas inside the balloon is at least a bit lighter?

Or is there some critical property I'm missing?

Please enlighten me, thank you.
 
Physics news on Phys.org
Do you recall that Gallileo dropped a feather off the Tower of Pisa, as well as a 1 pound weight and a ten pound weight:
http://www.jimloy.com/physics/galileo.htm
Astronauts tried Gallileo's experiment on the moon. See:
 
Last edited by a moderator:
If you fill a balloon up with your breath it would be mostly nitrogen just like the air you breathed in.

Also, with a density so close to that of the air it is prone to the slightest disturbances from the air.
 
Salbris said:
I've been racking my brain to figure this one out, I really don't understand it.

If you fill a balloon with air from your lungs, just manually blow it up, it should be carbon dioxide, no?

Density of Carbon Dioxide at Sea Level: 1.977 g/L
Density of Air at Sea Level: 1.2 g/L

So it's heavier. I know I'm pulling these numbers out of seemingly nowhere, but I'm sure someone can verify they are accurate.


So why on Earth would a balloon filled with a gas heavier than the surrounding gas in it's environment not drop at the normal speed. Aren't I right to think that bouyancy only takes effect when the gas inside the balloon is at least a bit lighter?

Or is there some critical property I'm missing?

Please enlighten me, thank you.
1] As pointed out, your exhaled breath is almost exactly the same as the air. It has an extra 5% CO2 and is shy by the same amount of oxygen.

2] You've got a volume of air, that weighs maybe a gram or two more than the surrounding air, but it has a giant surface area. It's terminal velocity is on the order of a few feet per second.
 
DaveC426913 said:
1] As pointed out, your exhaled breath is almost exactly the same as the air. It has an extra 5% CO2 and is shy by the same amount of oxygen.

2] You've got a volume of air, that weighs maybe a gram or two more than the surrounding air, but it has a giant surface area. It's terminal velocity is on the order of a few feet per second.

Ahh, Terminal Velocity. Now that makes sense. :)

Thanks for pointing that out.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top