Why Do Different Objects Share Similar Moments of Inertia?

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Different objects, such as a thin disk, cylinder, and thin hoop, share similar moments of inertia due to their geometric properties and the way mass is distributed relative to the axis of rotation. The moment of inertia for these shapes can be derived from the same integral, I = ∫ r² dm, which explains their equivalence when rotating about specific axes. The thin hoop's moment of inertia can be understood by projecting its rotation onto a plane, resulting in a shape similar to a disk. The discussion also highlights the use of the perpendicular axis theorem to analyze the hoop's moment of inertia. Overall, the similarities arise from the fundamental principles of rotational dynamics and mass distribution.
Cha0t1c
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Hello, I am a computer science major and Ex-Biology grad student, my knowledge in physics is humble, but I got a little curious when my professor derived the expressions of moment of inertia for different objects.

The moment of Inertia of a thin disk is 1/2MR2, but it is the same as the moment of Inertia for a cylinder and, surprisingly, the same for a thin hoop rotating about its diameter. So, in short:

I disk/perpendicular to axis of rotation = I Cylinder/perpendicular to axis of rotation= I thin hoop/through diameter

QUESTION:
How do we explain the similar moments of Inertia of the different objects?

My hypothesis concerning the moment of inertia of the thin hoop:
The hoop is rotating about its own diameter, if we take any point on the hoop and project its rotation on a plane perpendicular to the axis of rotation, we'll end up with a circle. Now, if we do the to every point on the hoop, we end up with a disk. Hence, the similar moment of inertia between the disk and the hoop!
 
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Hi,

$$I\equiv \int r^2\, dm$$
Disk and cylinder are the same because it's the same integral.
You can also think of a cylinder as a pile of disks,

Hoop is a little different. For your scenario you still have to show that the thickness of the 'disks' is a constant ...

Or, you could consider that the hoop is a planar object and use the perpendicular axis theorem
 

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