Why Do I Get Different Results When Calculating Powers and Indices?

  • Thread starter Thread starter peterspencers
  • Start date Start date
  • Tags Tags
    Algebra Indices
peterspencers
Messages
71
Reaction score
0
Hi there, I am stuck, please can someone help me to understand where I am going wrong...

I have been learning about indices and i am confused.. here is an example of why..

2t squared x 3t squared = 6t power 4

but if i give t a value of 2..

2x2 squared = 16

3x2 squared = 36

16 x 36 = 576

but... 6x2 power 4 = 20736

why am i getting two different answers, what am I doing wrong?
 
Mathematics news on Phys.org
(2*t)^2*(3*t)^2 is not the same thing as (6*t)^4 because if I expand them out, it comes out to be 36*t*t*t*t instead of (2*t)^2*(3*t)^2, and (6*t)^4 is 1296*t*t*t*t, which obviously do not equal each other unless t = 0.

I think you may be grouping them wrong, because if you simply move the parenthesis, you get 2*(t^2)*3*(t^2) = 6*(t^4) which is true because 2*(t^2)*3*(t^2) is the same thing as saying 6*t*t*t*t: I just multiplied the 3 and 2, and expanded the t^2's. 6*(t^4) is the same thing as saying 6*t*t*t*t as well, for the same reason, therefore they must equal each other.

If you are confused by the notation I am using, * means multiply, and ^ means to the power of.
 
peterspencers said:
Hi there, I am stuck, please can someone help me to understand where I am going wrong...

I have been learning about indices and i am confused.. here is an example of why..

2t squared x 3t squared = 6t power 4
There are better ways to represent what we in America call exponents.
1. Simplest - Use ^, which is notation that comes from the Basic programming language.
Your problem would appear as 2t^2 * 3t^2 = 6t^4
2. HTML tags - Click the Go Advanced button below the text input area. This causes the advanced menu to show across the top of the entry pane. The X2 button inserts tags around your exponent.
Your problem now looks like this: 2t2 * 3t2 = 6t4.
3. LaTeX script - I won't go into detail about how to do this, but you can find out more in this post: https://www.physicsforums.com/showpost.php?p=3977517&postcount=3.
With LaTeX script your equation looks like this:
##2t^2 \cdot 3t^2 = 6t^4 ##
If you right-click on what I wrote, you can see the script that did it.
peterspencers said:
but if i give t a value of 2..

2x2 squared = 16

3x2 squared = 36
No to both. If t = 2, then 2t2 = 2 * 22 = 8, and 3t2 = 3 * 22 = 12.
So when t = 2, 2t2 * 3t2 = 8 * 12 = 96.

On the other hand, 6t4 = 6 * 24 = 6 * 16 = 96.
peterspencers said:
16 x 36 = 576

but... 6x2 power 4 = 20736

why am i getting two different answers, what am I doing wrong?

Instead of squaring just the variable (i.e., 2t2), you are squaring the whole thing, (2t)2). These are different. Same for the other factor, 3t2.
 
Thankyou so much :)
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top