Why Does a Balloon Swing Forward When a Train Decelerates?

  • Thread starter Thread starter moneenfan
  • Start date Start date
  • Tags Tags
    Ball Train
moneenfan
Messages
5
Reaction score
0
you are on a train moving along a track at constant velocity. hanging from a switcase in an overhead luggage compartment is a balloon the end of a string. as long as the train continues at constant speed you observe the string is vertical . as you neer your destination you obsrve the ball swing forward slowly and come to rest at an angle of 8 degrees from the vertical

im having trouble understanding this.Im not sure if the ball is accelerating relative to the ground or not. I think it is. And I am not too sure how i would approach solving for the acceleration of the ball. Any ideas? I really want to better comprehend the question.
 
Physics news on Phys.org
What does the question ask you to find?
 
when it comes to rest at 8 degrees from the vertical the ball is stationary with respect to you. is it acceleration relative to the ground? What evidence do you have for or against the ball accelerating relative to the ground?

based on your observations the ball is the reference frame of the train, an inertial reference frame while the ball is hanging from the angle from the vertical. Explain?

What is the acceleration of the ball and what does this tell you about the motion of the train?
 
OK, well first of all: why does the ball not hang straight down?
 
well it does to begin with, but as the train begins to decelerate we have a change in velocity and it begins to accelerate negatively. We no longer maintain constant velocity and zero acceleration. Could it be that the ball while at constant velocity maintains itself relative to the floor of the trai and not the ground because there is zero acceleration?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top