Why does a conducting slab double a uniform incident field?

In summary, the presence of a conducting sheet perpendicular to a constant uniform incident field results in an overall total field that is double the incident field. This is due to the fact that the sheet's presence strengthens the field by pushing positive charges in the same direction as the incident field and pulling negative charges in the opposite direction. As long as the field due to the conducting sheet is transverse to the surface of the sheet, it is consistent with Gauss's law. In electrostatic equilibrium, the field inside the conductor is zero due to the rearrangement of charges on the sheet, while the field outside is not affected. The charge density on the surface of the conductor is given by σ = E/ε0, where E is the electric field outside
  • #1
OmegaKV
22
1
For a conducting sheet that is transverse to a constant uniform incident field, I believe the resulting total field would simply be the incident field doubled. I'm trying to figure out why this happens, preferably avoiding the method of images since I am using this to figure out how the method of images works.

What I have so far: The incident field will push positive charges in the sheet in the same direction that the incident field is pointing, and pull the sheet's negative charges opposite to the direction the incident field is pointing. It's clear from this that the sheet's presense will strengthen the field, but how do you know how much it strengthens the field? It seems to me that as long as the field due to the conducting sheet is transverse to the surface of the sheet, it is consistent with gauss's law, regardless of the magnitude.
 
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  • #2
OmegaKV said:
It's clear from this that the sheet's presense will strengthen the field,
It's exactly the opposite.
OmegaKV said:
The incident field will push positive charges in the sheet in the same direction that the incident field is pointing, and pull the sheet's negative charges opposite to the direction the incident field is pointing...
...which makes the net field inside the conducting sheet zero . The field due to rearrangement of the charges on the sheet (called 'induced charges') is in direct opposition with the incident field. Hence, electric field inside a conductor is always zero in electrostatic equilibrium.
 
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Likes vanhees71
  • #3
Sorry I meant the field outside of the conductor. I will draw a picture for clarity.

p6o27Y0.jpg


The yellow dots are negative charges and the purple dots are positive charges, and the field inside the conductor is zero. For an incident electric field pointing downward, how does the horizontal sheet affect the field outside of the conductor?
 
  • #4
It does not. The charge density σ on the surface of the conductor adjusts itself so that it is given by σ = E/ε0, where E is the electric field outside and ε0 is the usual constant.
 

Related to Why does a conducting slab double a uniform incident field?

1. Why does a conducting slab double a uniform incident field?

A conducting slab doubles a uniform incident field because of the phenomenon known as reflection. When an electromagnetic wave encounters a conducting material, the electrons in the material are able to move and create an opposing electric field. This results in a reflected wave that is equal in magnitude but opposite in direction to the incident wave. As a result, the total electric field in the conducting slab is the sum of the incident and reflected fields, resulting in a doubling of the original field.

2. How does a conducting slab affect the polarization of an incident field?

A conducting slab can affect the polarization of an incident field by changing the direction of the electric field. When a linearly polarized wave encounters a conducting slab, the reflected field is perpendicular to the incident field, resulting in a change in polarization. This is known as Brewster's angle and can be used to control the polarization of electromagnetic waves.

3. Why is a conducting slab transparent to electromagnetic waves of a certain frequency?

A conducting slab appears transparent to electromagnetic waves of a certain frequency because the electrons in the material are able to oscillate at that particular frequency. This results in a cancelled reflected wave, making the material appear transparent to that specific frequency. However, the slab will still reflect waves of other frequencies.

4. What determines the magnitude of the reflected field in a conducting slab?

The magnitude of the reflected field in a conducting slab is determined by the conductivity and thickness of the material. A material with high conductivity will have a greater number of free electrons to create a strong reflected field. Additionally, a thicker slab will result in a stronger reflected field as there is more material for the incident wave to interact with.

5. How does the angle of incidence affect the reflected field in a conducting slab?

The angle of incidence affects the reflected field in a conducting slab through the principle of total internal reflection. When the angle of incidence is greater than the critical angle, the incident wave will be completely reflected and there will be no transmitted wave. This results in a stronger reflected field as there is no loss of energy through transmission.

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