Why does a conducting slab double a uniform incident field?

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Discussion Overview

The discussion revolves around the behavior of a conducting slab in the presence of a uniform incident electric field. Participants explore the effects of the slab on the electric field, particularly focusing on the field inside and outside the conductor, and the implications of charge distribution on the slab.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the total field resulting from the incident field and the conducting slab would be doubled, questioning how this strengthening occurs without using the method of images.
  • Another participant counters that the presence of the conducting sheet actually leads to a zero electric field inside the conductor, as the induced charges oppose the incident field.
  • A later reply clarifies that the focus should be on the field outside the conductor, indicating that the charge density on the surface of the conductor adjusts to maintain a specific relationship with the external electric field.

Areas of Agreement / Disagreement

Participants express disagreement regarding the effects of the conducting slab on the electric field, particularly whether the field is strengthened or neutralized inside the conductor. The discussion remains unresolved regarding the implications for the field outside the conductor.

Contextual Notes

Participants reference Gauss's law and the concept of induced charges, but there are unresolved assumptions about the nature of the electric field and charge distribution in relation to the incident field.

OmegaKV
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For a conducting sheet that is transverse to a constant uniform incident field, I believe the resulting total field would simply be the incident field doubled. I'm trying to figure out why this happens, preferably avoiding the method of images since I am using this to figure out how the method of images works.

What I have so far: The incident field will push positive charges in the sheet in the same direction that the incident field is pointing, and pull the sheet's negative charges opposite to the direction the incident field is pointing. It's clear from this that the sheet's presense will strengthen the field, but how do you know how much it strengthens the field? It seems to me that as long as the field due to the conducting sheet is transverse to the surface of the sheet, it is consistent with gauss's law, regardless of the magnitude.
 
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OmegaKV said:
It's clear from this that the sheet's presense will strengthen the field,
It's exactly the opposite.
OmegaKV said:
The incident field will push positive charges in the sheet in the same direction that the incident field is pointing, and pull the sheet's negative charges opposite to the direction the incident field is pointing...
...which makes the net field inside the conducting sheet zero . The field due to rearrangement of the charges on the sheet (called 'induced charges') is in direct opposition with the incident field. Hence, electric field inside a conductor is always zero in electrostatic equilibrium.
 
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Sorry I meant the field outside of the conductor. I will draw a picture for clarity.

p6o27Y0.jpg


The yellow dots are negative charges and the purple dots are positive charges, and the field inside the conductor is zero. For an incident electric field pointing downward, how does the horizontal sheet affect the field outside of the conductor?
 
It does not. The charge density σ on the surface of the conductor adjusts itself so that it is given by σ = E/ε0, where E is the electric field outside and ε0 is the usual constant.
 

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