Why Does a Wire Melt? | Current & Resistance Explained

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Homework Help Overview

The discussion revolves around the phenomenon of a wire melting when excessive current is applied, focusing on the relationship between current, resistance, and resistivity. Participants explore the underlying physics principles, particularly Ohm's law and the concepts of heat generation due to electrical resistance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand why a wire melts under high current and seeks clarification on the relationship between current and resistance, as well as the distinction between resistance and resistivity. Other participants provide insights into the heat generated by resistance and the definitions of resistivity.

Discussion Status

Participants are actively engaging with the concepts, offering explanations about the heat generated from resistance and discussing the definitions of resistivity and resistance. There is a mix of interpretations regarding these concepts, and some participants are providing clarifications without reaching a consensus.

Contextual Notes

The original poster expresses uncertainty about the concepts and seeks help, indicating a potential lack of foundational knowledge in the subject area. The discussion includes attempts to clarify definitions and relationships between the physical quantities involved.

i.am.lost
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Hi all,

I have been set an experiment of relating to the current needed to melt a wire (predominantly dealing with R = ρL/A). This sounds like a really dumb question (because it is :redface:) but why does the wire melt when too much current is passed through?

Also, what is the correlation between the current that would melt a wire and the wire's resistance? And what the heck is the difference between resistance and resistivity (let me guess, resistivity is a standard measure, whereas resistance is length-dependent??)

Any help would be great. Many thanks you guys, and hope your day is going good.
 
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The wire melts due to generated heat (given by P = I^2/R and the heat capacity of the wire) which of course comes from resistance.

Resistivity is just a sort of "resistance density" if you will. In classical physics you have a lot of these "density" type quantities like pressure, density (who'd have thought), etc. It's resistance per unit length, and nothing more - ohms per metre, Ω/m, Ωm^-1, etc, etc. Resistance is length dependent as you say.

A little bit of dimensional analysis goes a long way here.
 
Note that the unit of resistivity is Ohm metre Ωm and not Ω/m.
 
dst said:
Resistivity is just a sort of "resistance density" if you will. In classical physics you have a lot of these "density" type quantities like pressure, density (who'd have thought), etc. It's resistance per unit length, and nothing more - ohms per metre, Ω/m, Ωm^-1, etc, etc. Resistance is length dependent as you say.
It's resistance per unit length, and nothing more - ohms per metre, Ω/m, Ωm^-1, etc, etc.

Not exactly. :smile:

If the resistivity of a wire 2m long and having area of cross-section [tex]1 cm^2[/tex] is 5 Ωm, then the resistance is not 5*2 Ω. Resistance will be [tex]\frac{5*2}{0.0001}[/tex]Ω
 
Last edited:
Due to resistance there is a drop in potential. This potential energy is converted into heat energy and if the T reaches the melting point of the wire, it melts!
 

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