Why does alternate way of solving the problems not work?

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The discussion revolves around calculating the work done by air resistance on a 7 kg ball dropped from 20 meters, which reaches a speed of 18 meters per second before hitting the ground. The potential energy (PE) is calculated as 1400 joules, and the kinetic energy (KE) without air resistance would be 20 meters per second, leading to a discrepancy of 2 meters per second. The participant calculates the kinetic energy for the reduced speed of 18 m/s and questions why this value does not represent the work done by air resistance. The conversation highlights the complexity of energy conservation principles, noting that the loss of mechanical energy due to air resistance is transformed into thermal energy, complicating straightforward calculations. Understanding these concepts is crucial for accurately determining the effects of air resistance on falling objects.
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Homework Statement



Princeton p 411 #6

A 7 kg ball is dropped from 20m. if the speed just before it hits the ground in 18 meters per second, what is the work done by air resistance?[/B]

Homework Equations


KE= (mv^2)*1/2
PE=mgh[/B]

The Attempt at a Solution


Mgh equals 1400 joules. PE equals KE. using the kinetic energy formula I was able to derive that the velocity of the ball without air resistance would be 20 meters per second. Which would be 2 meters per second less than 18 meters per second. Then I calculated the amount of kinetic energy there would be for 2 meters per second he found that it would be 14 joules. Why isn't this the answer for the amount of air resistance? I know how to find the right answer, but why doesn't this work?[/B]
 
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Perseverence said:

Homework Statement



Princeton p 411 #6

A 7 kg ball is dropped from 20m. if the speed just before it hits the ground in 18 meters per second, what is the work done by air resistance?[/B]

Homework Equations


KE= (mv^2)*1/2
PE=mgh[/B]

The Attempt at a Solution


Mgh equals 1400 joules. PE equals KE. using the kinetic energy formula I was able to derive that the velocity of the ball without air resistance would be 20 meters per second. Which would be 2 meters per second less than 18 meters per second. Then I calculated the amount of kinetic energy there would be for 2 meters per second he found that it would be 14 joules. Why isn't this the answer for the amount of air resistance? I know how to find the right answer, but why doesn't this work?[/B]
Kinetic energy varies as the square of velocity. ##(v+2)^2 - v^2 \neq 2^2##.
 
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With no friction/air resistance the total energy is conserved. With friction/air resistance the loss of total mechanical energy is converted to thermal energy. In this case heating of the projectile and the air it passes through.
 
Dr Dr news said:
With no friction/air resistance the total energy is conserved. With friction/air resistance the loss of total mechanical energy is converted to thermal energy. In this case heating of the projectile and the air it passes through.
All true, but sadly nothing to do with the question Perseverence asked, and most likely all well understood by the student already. See tnich"s answer.
 
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