Why Does an Object Fall 490 Meters in 10 Seconds?

[tman]

An object falls because of gravity at a rate of -980 cm/sec2 (- sign is indicative of a downward direction) for 10 seconds. If it starts from rest (vo= 0) and its position starts from do= 0, where is it 10 seconds later?

_______________m

I don't know where to start

 

[tman]

maybe use d=1/2vt but what do I plug in

 

[arildno]

maybe use d=1/2vt but what do I plug in

Whatever is this??

You have constant acceleration, how is distance as a function of time given in that case?

 

[Raza]

I think it is 980m

 

[tony873004]

If every second, it is moving 980 cm / second faster, then how fast is it going in 10 seconds?

v = a * t

what is its average velocity during this 10 second peroid? Hint: It started at 0, it ended at a*t. Take the average.

Now distance is easy. It traveled an average velocity for a known time.

d=1/2vt

This formula is wrong.
d = vt

Following the logic above, you should be able to come up with the correct formula for d using a (acceleration) instead of v (veolcity).

I think it is 980m

This is wrong too. How did you get this? Watch your units. You expressed acceleration in cm, but your answer in meters, which is ok to do, but make sure you convert properly.

 

[phreak]

Just use this formula

\Delta x = \frac{1}{2}at^2

Input the values and solve. -4.9m(100s)

-490 meters from its original position