Why Does Calculating Bullet Transit Time Yield Different Results?

AI Thread Summary
Calculating the bullet's transit time through the target requires considering the target's movement, as it affects the distance the bullet travels while inside. The initial calculation used only the thickness of the target and the bullet's final speed, leading to an incorrect result. The correct approach involves using the average speed of the bullet while it is in the target, which is derived from both its initial and final velocities. This method yields a transit time of 4.0 x 10^-4 seconds, aligning with the expected answer. Accurate calculations must account for both the bullet's speed and the target's motion to avoid discrepancies.
ZzZerozZ
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In a ballistics test, a 25.0g bullet traveling horizontally at 1100m/s goes through a 40.0cm -thick 250kg stationary target and emerges with a speed of 900m/s . The target is free to slide on a smooth horizontal surface.

the 1st question of this problem ask: How long is the bullet in the target?

I simply do:

40.0cm=0.4m ; 0.4m/(900m/s)=4.4*10^-4

The answer shows 4.0*10^-4

Did I make a mistake or it is just a rounding problem?
 
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Hi ZzZerozZ! Welcome to PF! :smile:

i] in your distance/speed, you've used the width of the block as the distance, but the block is moving, so the distance is longer

ii] your speed is the final speed, so it's too small :redface:
 
ZzZerozZ said:
In a ballistics test, a 25.0g bullet traveling horizontally at 1100m/s goes through a 40.0cm -thick 250kg stationary target and emerges with a speed of 900m/s . The target is free to slide on a smooth horizontal surface.

the 1st question of this problem ask: How long is the bullet in the target?

I simply do:

40.0cm=0.4m ; 0.4m/(900m/s)=4.4*10^-4

The answer shows 4.0*10^-4

Did I make a mistake or it is just a rounding problem?

Using s = (u+v)/2 *t the answer is 4 *10^-4. s= distance, u = inital vel, v= final vel.
 
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