Why does charge on a pointy conductor not uniformly spread?

AI Thread Summary
Charge on a spherical conductor distributes uniformly due to its symmetrical shape, while on a conical conductor, it does not. The concentration of charge is higher near the tip of the cone because the surface area is smaller there compared to other parts of the conductor. This uneven distribution occurs because the motion of electrons within the conductor is fluid, allowing charge to move until equilibrium is reached. The confusion arises from the misconception about surface area at the vertex versus a flat surface. Understanding the geometry of the conductor is crucial to grasping how charge distributes.
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Homework Statement


If charged is place on a spherical conductor, it distributes uniformly. If charged is placed on a conical conductor, it does not spread uniformly.

Homework Equations


Remember that, in a conductor, the motion of electrons is fluid.

The Attempt at a Solution


Taking the given example, a cone, if we placed charge on it, charge would spread. It would spread in the sense that every square centimeter would have a constant charge. Because surface area clumps near the cone's tip, however, charge would be more concentrated there.

I get the impression that this attempt is bogus. I don't see why a surface's surface area is greater at a vertex than on a flat plane.
 
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