Why Does Connecting Multiple Ohmmeters Result in Cumulative Resistance?

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Connecting multiple ohmmeters to the same resistor can result in cumulative resistance readings due to the way each meter interacts with the circuit. When two ohmmeters are connected, each injects its own current, leading to an increase in the total current flowing through the resistor, which can cause the meters to interpret the resistance incorrectly. This occurs because the combined current from both meters can affect the voltage drop across the resistor, leading to higher resistance readings than expected. Essentially, each meter's internal circuitry interprets the lower current as a higher resistance, resulting in a cumulative effect. Understanding this interaction is crucial for accurate resistance measurements in multi-meter setups.
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This might be a forehead-slap moment but I'll ask anyway...

I'm working on a project building a panel of ohmmeters that will simultaneously measure the line-to-line resistance values a 3-phase generator and was running into trouble connecting all three ohmmeters to the three-phase measurement point, where two would read accurately and the third always reads a combination of the other two. So I ran a quick experiment, taking two ohmmeters with separate 9V power sources. When each is connected individually to a 4.7 ohm resistor, they read 4.7 ohms. When you connect them both to the same resistor simultaneously they both read 9.4 ohms. I'm hoping someone more familiar than me with test equipment can tell me why they display cumulative resistance when both connected to the single resistor (I was under the impression an ohmmeter would always display the lowest possible resistance between the test leads).
 
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To measure a resistance, some meters inject a current and read the resulting voltage...
 
(I was under the impression an ohmmeter would always display the lowest possible resistance between the test leads).
An ohmmeter means one (1) ohmmeter.

think about it, crudely as,
A nine volt nominal source across a 4.7 R -> current through the resistor is 2 A.
Now connect a second nine volt nominal supply -> each source sends 1 A through the resistor, for the resistor to have still the nominal 9 v across it.

The second time, the guts of this "ohmmeter" will interpret the lessor current as a higher resistance than before.
 
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