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Why does corrected Maxwell Boltzmann have decimals?

  1. May 14, 2015 #1
    So I have just been reading up on statistical thermodynamics and have no idea why the bose-einstein, fermi dirac and maxwell boltzman are all integers, that makes sense, but then when you make the degenerate correction to the maxwell boltzmann by dividing by N! we get decimal answers. Why is this?

  2. jcsd
  3. May 14, 2015 #2


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    Staff: Mentor

    What do you mean with "all integers"? There are several expressions that are not integers.
    Unrelated: does the difference between 46444364765232142364752464 and 46444364765232142364752464.3 matter? Arbitrary numbers of course.
  4. May 15, 2015 #3


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    Because it is only an approximation.
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