Why does friction act in the normal direction

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SUMMARY

The discussion clarifies the role of friction in circular motion, specifically addressing a scenario where cartons of mass 5kg move at a constant speed of 8 m/s on a conveyor. The coefficients of static and kinetic friction are 0.7 and 0.5, respectively. It is established that in this context, the frictional force acts as the centripetal force, pointing inward rather than in the tangential direction. The importance of presenting clear and complete questions in physics forums is emphasized to avoid misunderstandings.

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zachdr1
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For a particle undergoing a constant velocity circular motion. I thought friction always acted in the direction of motion which would be in the tangential direction.
 
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zachdr1 said:
I thought friction always acted in the direction of motion...
Kinetic friction acts opposite to relative motion at the contact. Static friction can point in any direction parallel to the contact plane.
 
A.T. said:
Kinetic friction acts opposite to relative motion at the contact. Static friction can point in any direction parallel to the contact plane.
So how do you determine the direction of static friction?
 
zachdr1 said:
So how do you determine the direction of static friction?
Depends on what else is known.
 
A.T. said:
Depends on what else is known.

How about for this problem?

Cartons having a mass of 5kg are required to move along the assembly line at a constant speed of 8 m/s. Determine the smallest radius of curvature for the conveyor so the cartons do not slop. The coefficients of static and kinetic friction between a carton and the conveyor are .7 and .5 respectively
 
zachdr1 said:
How about for this problem?
Since friction is the only horizontal force its direction should be obvious.
 
zachdr1 said:
How about for this problem?

Cartons having a mass of 5kg are required to move along the assembly line at a constant speed of 8 m/s. Determine the smallest radius of curvature for the conveyor so the cartons do not slop. The coefficients of static and kinetic friction between a carton and the conveyor are .7 and .5 respectively
Show us your free body diagram.
 
zachdr1 said:
For a particle undergoing a constant velocity circular motion. I thought friction always acted in the direction of motion which would be in the tangential direction.

zachdr1 said:
How about for this problem?

Cartons having a mass of 5kg are required to move along the assembly line at a constant speed of 8 m/s. Determine the smallest radius of curvature for the conveyor so the cartons do not slop. The coefficients of static and kinetic friction between a carton and the conveyor are .7 and .5 respectively

Boys and girls. This example is why we insist that you present your question clearly and fully, and with the CONTEXT. Otherwise, we will give you apples, when what you're asking are oranges!

When the OP asked the problem, it appears as if this is a normal, sliding mass problem, in which of course the frictional force is NOT in the normal direction.

However, it is ONLY after the OP presented the ACTUAL problem do we see what it really is! In this problem, the frictional force is the one providing the centripetal force! So this is not the same problem and with a different context than earlier. In this case, the frictional force/centripetal force points inwards (not in the normal direction).

The OP needs to present this in the HW section of the forum and, as Chestermiller has stated, he/she needs to show the free-body diagram.

So moral of the story: when we ask you to post your question in full and as clearly as possible, this is the VERY reason why! Without context, one can have a widely-varying scenario that is possible from a vague question.

Zz.
 
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ZapperZ said:
the frictional force/centripetal force points inwards (not in the normal direction).
Yes, "normal" is ambiguous. In the context of friction it usually means normal to the contact surface, but the OP meant normal to the path of the object.
 
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A.T. said:
Yes, "normal" is ambiguous. In the context of friction it usually means normal to the contact surface, but the OP meant normal to the path of the object.

Which again, is another reason why we insist on a clear and complete post. I think a lot of people somehow assumed that we can read what's in their heads, whereas many of the terms being used in physics already have a clear definition which may be different than what they are thinking of.

The art of clear communication is something that one can acquire only via practice, and this forum is a very good place to practice.

Zz.
 

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