Why Does Hydrogen Peroxide Fizz Only on Wounds?

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Hydrogen peroxide (H2O2) is used for wound sterilization, and its fizzing indicates a chemical reaction. The bubbles produced are primarily due to the release of atomic oxygen, which is the active agent that kills bacteria, rather than diatomic oxygen (O2). The fizzing occurs specifically on wounds because they contain organic material that reacts with H2O2, unlike normal skin or inert surfaces. The reaction does not spontaneously revert to water in the bottle due to the stability of hydrogen peroxide in its stored form. The discussion highlights the importance of understanding the chemical reactions involved, correcting misconceptions about the nature of the oxygen released, and clarifying the reaction dynamics.
DaveC426913
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Been using H_2 O_2 to sterilize a wound. I notice that it fizzes.

1] I presume the bubbles it releases are O_2. i.e. 2 H_2 O_2 > 2H_2 O + O_2
2] I further presume it is the O_2 that kills the bacteria.

And that makes me wonder:
3] I notice that it only fizzes on my wound - it does not fizz when applied to normal skin (or the container it comes in, or the Q-tip). Although it does fizz when poured into the drain. It seems to zero in on organic material.

I am guessing this is because:
- my skin has an oily (i.e. water repellant) coating that the peroxide can't react on/with, or
- the wound has chemically active components that normal skin will not expose, or
- the wound has physically reactive components - like the miscroscopic nicks in a champagne glass that serve as bubble nurseries (I forget the name)

4] Also, why does it not spontaneously revert to water in the bottle? Even over a long time?


Thoughts?
 
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1.Yes,the reaction u've discribed is incorrect...The correct redox is:

H_{2}O_{2}\rightarrow H_{2}O+O

which means the one atom gets reduced and another oxydated...Note that atomic oxygen is the powerful oxydating agent...So not O_{2} kills bateria (it would be ridiculous,why need hydrogen peroxyde,then),but atomic oxygen...

Daniel.
 
Thank you. I don't think I could have gotten a more comprehensive answer if I'd written the question after reading the answer!

P.S. dexter: you might want to read it too. It specifies pretty much the exact reaction I did:

H2O2 --> H2O + O2

(I think your and their answer are ultimately equivalent, you are just concentrating on a discrete intermediate step).
 
no actually your equation isn't balanced making it wrong. It is a two step reaction as oxygen isn't going to stick around in its monatomic form for long but if it was immediately just diatomic then the air would be as good a bacteriocide as hydrogen peroxide.
 
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