Why does Lim as x approaches infinity of x/(x-9) = 1?

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Homework Statement



Limit as x approaches infinity of x/x-9

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The Attempt at a Solution



I know the indeterminate form infinity/infinity happens. I don't know how to fix it, but I'm assuming it's quite simple...
 
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When x is very very large, say 6 billion. The numbers 6 billion and 6 billion minus 9 are essentially the same. As x gets larger and larger, this discrepancy diminishes. The value the ratio approaches is 1.

If you wanted to be a little more rigorous, you can divide the numerator and denominator by 1/x then take the limit and see what happens. It should pop right out.
 
A nice trick for these types of problems would be to divide everything by x;

\lim_{x\rightarrow\infty} \frac{x/x}{(x/x)-(9/x)}

Then simplify and you should be able to figure it out from there
 
Using L'Hopitals rule for evaluating indeterminate forms, just differentiate both the numerator and the denominator separately to produce 1/1. Xyius explains well intuitively why the result is what it is.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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