Phrak said:
OK, I did. How does a decreasing dielectric constant of water with increased temperature reduce solubility?
Hi Phrak !
Reduce solubility? Well it depends on which substance is being added to water. Presumably I think you are talking about methyl cellulose.
Dielectric constant is the property due to which water has the ability of electrostatic charge separation and can dissolve various (nearly all) substances especially electrovalent compounds and hence is known as dielectric constant. Due to this property only water acquire a very strong polar covalent bond.
H
2O ----------> H
+ + OH
-
Now
H
+ + H
2O ---------------> H
3O
+
Overall equation :
2H
2O --------------> H
3O
+ + OH
-
[C
6H
7O
2(OH)x(OCH
3)
y]
n is the formula of methyl cellulose (stolen from
http://www.fao.org/ag/agn/jecfa-additives/specs/Monograph1/Additive-277.pdf)
H3Oδ+
OHδ-
[C6H7O2(OH)x(OCH3)y]n
where δ is delta here represents net charge.These have high
electric dipoles and hence can easily dissolve various substances.
Solubility curves : Temperature vs solubilitySo now you see that in many cases some substances behave differently.
For instance is case of solids solubility of Caesium Sulphate [ Ce
2(SO
4)
3 ] and Calcium Sulphate [ CaSO
4 ] is decreasing with rise in temperature. There are reasons for it but I can't explain them here.
Solubility curves : Pressure vs solubility
Answer to your question : If you reduce dielectric constant of water then solubility of methyl cellulose will decrease. But if you increase the temperature then its solubility will decrease at the greater rate. This is because methyl cellulose is more covalent in nature than electrovalent or ionic. On increasing the temperature it uses that heat energy to increase its bond statistics like increasing the vander waals forces. Hence the solubility will decrease.
Hope this helps :) .