Why Does qEt/m Represent Drift Speed in a Conductor?

  • #1
anonymousphys
29
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Homework Statement


v=qEt/m
t=time between each collision
q=charge on particle
m=mass of particle
E=electric field

Why is this the average velocity/drift speed in a conductor?



Homework Equations





The Attempt at a Solution



Doesn't qEt/m = the final velocity of the particle. So isn't the average velocity qEt/(2m)?
Is there something missing in my logic?

Thanks for any help.
 
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  • #2
Still not too sure about this problem. Any help would be much appreciated.
 
  • #3
In in introductory physics, do we just assume qEt/(2m) = qEt/(m) because the values are so small?
 

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