Why Does Separation Point Move Downstream with Increasing Reynolds Number?

AI Thread Summary
The discussion centers on why the separation point on a circular cylinder moves downstream with an increasing Reynolds number. As Reynolds number increases, the boundary layer becomes less influenced by viscosity, leading to a delayed separation point. This is attributed to the relationship between velocity and dynamic viscosity, where higher speeds reduce the effects of viscosity on the flow. The conversation references boundary layer theory, emphasizing that at higher Reynolds numbers, the flow remains more attached to the surface of the cylinder. Understanding these dynamics is crucial for predicting flow behavior in fluid mechanics.
jjiimmyy101
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Probably a simple question, but I could use some clarification please.

When we have flow over a simple geometric shape (i.e. a circular cylinder) why does the separation point move further downstream as Reynolds number increases?

Does it have anything to do with pressure difference (I think it does) but what?

Any thoughts please.
 
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Well, its a good question

We have Reynolds Number, Re = (density x velocity x length)/dynamic viscosty

Seperation occurs due to boundary layer phenomena. and boundary layer is directly proportional to friction (viscosity). i.e., if viscosity rises boundary layer also rises.
lets move to our problem, Increasing Re moves separation point away from the body.
assume its incomressible flow (density constant), and length remains constant. Now the only variables are velocity and dynamic viscosity. At higher speeds, boundary layer effects are less over the body, since viscocty has no effect on the body at high speeds.

@boundary layer theory by schichting for reference
 
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