Why does the linear antenna radiate at k^2?

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The discussion centers on the radiation characteristics of a linear dipole antenna as described in Jackson's classical electrodynamics. It highlights a discrepancy in the equations regarding the power radiated by a dipole, noting that while the total power is typically proportional to k^4, the linear antenna appears to radiate at k^2. This is attributed to the dipole moment's dependence on frequency, leading to a reduction in the effective power relationship. The participants agree that the presence of the ω term in the dipole moment affects the overall power calculation. Ultimately, the conclusion is that the dipole's radiation power is indeed proportional to k^2 due to these factors.
qnach
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I am reading Jackson's book on classical electrodynamics.
It said in page 412 to 415 (3rd edition) that the total power radiated by a
dipole is proportional to k^4 (equation 9.24)
quadrupole is proportional to k^6 (equation 9.49)
But why does the linear antenna at page 412, which is a dipole, radiate at k^2 (equation 9.29)?
 
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The dipole moment, p, has ω in the denominator (equation 9.27). Thus the c2|p|2 terms in 9.24 replace two of the k's.
 
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so the (real) power for a dipole should be proportional to k^2 instead of k^4 ?
 
Yes
 
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