Why Does the Recoiling Cannon's Projectile Angle Calculation Seem Incorrect?

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The discussion focuses on the calculation of the projectile's angle relative to the ground after being shot from a recoiling cannon. The cannon's mass is 4500 kg, tilted at 30°, and fires a projectile at 60 m/s, resulting in a recoil speed of 0.5 m/s. The user attempts to calculate the angle using the formula tan θ = (60sin30) / (0.5 + 60cos30) but finds the result incorrect. A key point raised is the necessity of knowing the projectile's mass to accurately determine its horizontal velocity and angle. The conservation of horizontal momentum is emphasized as crucial for solving the problem correctly.
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A circus cannon, which has a mass M = 4500 kg, is tilted at q = 30°. When it shoots a projectile at v0 = 60 m/s with respect to the cannon, the cannon recoils along a horizontal track at vcannon = 0.5 m/s with respect to the ground.

a) At what angle to the horizontal does the projectile move with respect to the ground?

I get tan \theta = 60sin30 / (0.5+60cos30). But it's still wrong. Can someone tell me what I did wrong? Thanks
 
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In this question the horizontal momentum is conserved, so you know that the final momentum of the cannon equals the final horizontal momentum of the projectile.
are you sure that you don't know the mass of the projectile? If you knew the mass then with that you could find the horizontal velocity and then the angle.
 
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