Why Does the Scale Reading Change in an Accelerating Elevator?

AI Thread Summary
In an accelerating elevator, the scale reading changes due to the combined forces acting on the woman and the elevator. The woman has a mass of 58.5 kg, while the elevator and scale together weigh 815 kg. The net force during the upward acceleration is calculated using the equation Fnet = ma, considering both the weight of the woman and the elevator. The initial calculations neglected the woman's mass, leading to an incorrect scale reading. Correcting for her mass results in a scale reading of approximately 636.89 Newtons during the elevator's acceleration.
keemosabi
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Homework Statement


A woman stands on a scale in a moving elevator. Her mass is 58.5 kg, and the combined mass of the elevator and scale is an additional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9510 N. What does the scale read during the acceleration?


Homework Equations


Fnet = ma


The Attempt at a Solution


I found the acceleration of the entire elevator by doing 9510 - 815(9.8) = 1523. I divided this by 815 to get 1.8687. It is in the negative direction, so it is -1.8687 If this is the acceleration of the elevator, it must also be the acceleration of the person. As a result, I did Fnet = ma, Fnet = (58.5)(-1.8697) and got Fnet = 682.31895. I put 682.31895 as the what the scale reads but it says I got the answer wrong. What did I do incorrectly?
 
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How many scales have you stepped on that give a reading in Newtons? When you are in an elevator that starts going up, do you feel momentarily heavier or lighter?
 
D H said:
How many scales have you stepped on that give a reading in Newtons?
The space to fill in the answer requests that it be given in Newtons.
When you are in an elevator that starts going up, do you feel momentarily heavier or lighter?
I believe you feel momentarily heavier.
 
keemosabi said:
Her mass is 58.5 kg, and the combined mass of the elevator and scale is an additional 815 kg.

I found the acceleration of the entire elevator by doing 9510 - 815(9.8) = 1523. I divided this by 815 to get 1.8687.

What did I do incorrectly?

You forgot about the mass of the woman.
 
D H said:
You forgot about the mass of the woman.
Is that because it says that the elevator and the scale provide an additional mass?
 
Yes. That's why I highlighted the word additional.
 
Code:
9510 - 815(9.8) = 1523. I divided this by 815 to get 1.8687.

So basically just add 58.5 to each of those calculations where I used 815?
 
What does that get you?
 
D H said:
What does that get you?
It accounts for the weight of the woman in all of my calculations.
 
  • #10
So is the answer 636.8895?
 
  • #11
I get a very slightly different answer from your 636.8895 Newtons.

From your first post, it appears you are using some electronic form that tells you whether your answer is correct. Did it accept 636.8895 Newtons? If it did not accept that, show your work.
 
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