Why Does UV Light Cause Sunburn But Visible Light Does Not?

AI Thread Summary
UV light causes sunburn due to its higher photon energy compared to visible light, which does not have enough energy to damage organic molecules in the skin. The discussion highlights the relationship between photon energy and its ability to cause damage, referencing the photoelectric effect as a parallel. It emphasizes that the frequency of light, rather than intensity, determines its potential to induce reactions in materials. The damage from UV light leads to sunburn, while visible light lacks the necessary energy to trigger similar effects. Understanding these principles clarifies why UV exposure is harmful to skin.
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Homework Statement



UV light causes sunburn, whereas visible light does not. Explain.

Homework Equations



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The Attempt at a Solution



I'm guessing that it might have sinething to do with the electromagnetic spectrum.
 
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Probably. Since it's electromagnetic. Might have something to do with the energy of photons as well. Can you give this a little more thought?
 
Is it because in UV light, the energy of the photons is much greater than the energy of photons in visible light?
If so, why does the energy of the photons have anything to do with getting sunburn?
 
Because sunburn is caused bythe photons causing damage to organic molecules. What might 'causing damage' have to do with the energy of the photons? Think photoelectric effect.
 
lol... photelectric effect, bits of my skin being imparted with energy and flying off my body?
 
"Photoelectric effect" as in some processes require a minimum photon energy to proceed.
 
You have probably seen a demonstration of the photoelectric effect once, where your teacher shines a lamp on a cathode/anode device. You might remember that not the intensity, but the frequency (color) of the light was what decided if and how much electrons are released. The same concept applies here.
 
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