Why Does Zin Calculation Differ in Single Stub Matching?

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The discussion centers on a discrepancy in the Zin calculation during single stub matching, where the load impedance zl is 0.5 + 1.5i. Despite using both a Smith chart and analytical methods to match to a normalized line with Z0=50, the calculated Zin does not match the expected result of 0.5 + 1.5j. The issue arises from a potential error in the matching process, as the second image shows a different impedance of 0.5 - j1.5. Clarification is sought on the source of this inconsistency. Understanding the correct application of the Smith chart and impedance transformation is crucial for accurate results.
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Hello
As you see this problem with single stub matching
I matched zl=.5+1.5i to a normalized line (Z0=50)(I did it with smith chart and analytically) but as you see in the second picture as I calculate Zin it doesn't get me the same result (.5+1.5j).
2390138400_1435297056.jpg
what is my wrong?
 
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baby_1 said:
Hello
As you see this problem with single stub matching
I matched zl=.5+1.5i to a normalized line (Z0=50)(I did it with smith chart and analytically) but as you see in the second picture as I calculate Zin it doesn't get me the same result (.5+1.5j).
2390138400_1435297056.jpg
what is my wrong?
In the first picture the load is 0.5 + j1.5 and in the second it is 0.5 - j1.5.
 
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