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Why doesn't a dineutron system form a bound state?

  1. Jan 14, 2012 #1
    Why doesn't a dineutron system form a bound state?????

    Why doesn't 2 neutrons with one spin up and the other spin down form a bound state but a neutron and proton with both spin up or down form a bound state
     
  2. jcsd
  3. Jan 14, 2012 #2
    Re: Why doesn't a dineutron system form a bound state?????

    Another question , Is the binding energy per nucleon (assuming A is small enough) stronger for a p-n nucleus with one spin up and the other spin down than a p-n nucleus with both spin up or down?
     
  4. Jan 14, 2012 #3
    Re: Why doesn't a dineutron system form a bound state?????

    Of the possible bound states for two nucleons, the ground state is 1H2, so a state of two neutrons would decay to this via the weak force.
     
  5. Jan 14, 2012 #4
    Re: Why doesn't a dineutron system form a bound state?????

    Ok , but Why doesn't the 2 neutrons form a ground state???
     
  6. Jan 14, 2012 #5

    tom.stoer

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    Re: Why doesn't a dineutron system form a bound state?????

    Because of the spin and isospin symmetry properties of the nucleon-nucleon force.

    If I remember correctly wer had this discussion here a coupleof times; please search for "dineutron" or something like that.
     
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