Why In Struvite formation HPO42- is favored over PO43-?

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SUMMARY

The discussion centers on the formation of Struvite (MgNH4PO4.6H2O) and the preference for HPO42- over PO43- in this process. Optimal pH for Struvite formation is identified as being between 7 and 10.9, where HPO42- predominates. The deprotonation of HPO42- to PO43- is not spontaneous, with a Gibbs free energy change of approximately 30.6 kJ mol-1, suggesting that the reaction favors HPO42- due to the energy cost associated with deprotonation. The conversation highlights the importance of considering both phosphorus and ammonium species in the solubility dynamics of Struvite.

PREREQUISITES
  • Understanding of acid-base equilibria, particularly pKa values.
  • Knowledge of solubility product constants (Ksp) for ionic compounds.
  • Familiarity with the chemistry of magnesium, ammonium, and phosphate ions.
  • Basic proficiency in calculating pH and its impact on solubility.
NEXT STEPS
  • Research the role of pH in the solubility of Struvite and other phosphate minerals.
  • Study the thermodynamics of deprotonation reactions, focusing on Gibbs free energy changes.
  • Explore the implications of ammonium ion (NH4+) conversion to ammonia (NH3) in aqueous solutions.
  • Investigate the crystallization processes of Struvite and other similar compounds in wastewater treatment.
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Chemists, environmental engineers, and researchers involved in wastewater treatment and nutrient recovery who are interested in the dynamics of Struvite formation and solubility.

demander
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Cheers community, I have been studying the Struvite formation from respective ions. Being the general formula for Struvite MgNH4PO4.6H2O I intuitively tought the reaction would be
Mg2+ + NH4+ + PO43- + 6H2O↔ MgNH4PO4.6H2O.

However from literature and from practice, not only the optimal pH seems to be around the range from 7 to 10/11 where HPO42- is predominant as when Struvite forms tends to slightly decrease the pH of solutuon, which gives an hint for the release of a proton(H+), what suggests the real formula for struvite is
Mg2+ + NH4+ + HPO42- + 6H2O↔ MgNH4PO4.6H2O + H+.

My question is wouldn't it be more favorable for the system to generate Struvite directly from PO43- instead of HPO42-? doesn't it create a further energy consuming step for the deprotonation of the Hydrogen Phosphate?
From what I checked being pKa = 12.346 for reaction HPO42- = H+ + PO43-, the Free energy Gibbs Variation is ≅30,6 kJ mol-1, implying from what I know that this deprotonation step is not a spontaneous reaction.

Might there be a reason I'm negleting or forgetting that might explain why this reaction is driven by HPO42- instead of PO43-?

Thanks in advance for any insight you might have.
 
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I think at higher pH values, rather than NH4+, NH3 would be the predominant species in solution which is not even ionic and therefore might be more difficult to embed into the crystal lattice.
 
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I just tried to calculate the pH where the solubility of Struvite is minimal. If I got my maths right, the optimal pH is ##(\mathrm{pK_a(HPO_4^{2-})+pK_a(NH_4^{+}))/2 }##, which is about 10.9.
 
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Thank you DrDu, I was so focused on Phosphorus I didn't thought to remember the NH4+ turning to NH3 an evolving from solution.
DrDu said:
I just tried to calculate the pH where the solubility of Struvite is minimal. If I got my maths right, the optimal pH is ##(\mathrm{pK_a(HPO_4^{2-})+pK_a(NH_4^{+}))/2 }##, which is about 10.9.
That is an inteteresting value. What expression(s) did you use to get there to this sum of Pkas I don't remember this experession(maybe because I was too many years without working with solutions)?
 
I used the equations
##
K_{sp}=[Mg^{2}][NH_4^+][PO_4^{3-}] ##
## K_a(NH_4^{+})= [NH_3][H^+]/[NH_4^+]##
##K_a(HPO_4^{2-})=[PO_4^{3-}][H^+]/[HPO_4^{2-}]##
##[Mg^{2+}]=[NH_3]+[NH_4^+]=[HPO_4^{2-}]+[PO_4^{3-}]##
And looked for a minimum of ##[Mg^{2+}]## as a function of ##[H^+]##.
 
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