Why In Struvite formation HPO42- is favored over PO43-?

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The discussion centers on the formation of Struvite (MgNH4PO4.6H2O) and the role of ions in its synthesis. It highlights that the optimal pH for Struvite formation is between 7 and 10/11, where HPO42- is the predominant species, suggesting that the reaction involves the release of a proton (H+). The inquiry raises whether it would be more efficient to generate Struvite directly from PO43- rather than HPO42-, noting that the deprotonation of HPO42- is not spontaneous due to its Gibbs free energy variation. Additionally, the conversation touches on the transition of NH4+ to NH3 at higher pH levels, which complicates the crystal lattice formation. The optimal pH for minimal Struvite solubility is calculated to be around 10.9, based on specific equations involving pKa values.
demander
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Cheers community, I have been studying the Struvite formation from respective ions. Being the general formula for Struvite MgNH4PO4.6H2O I intuitively tought the reaction would be
Mg2+ + NH4+ + PO43- + 6H2O↔ MgNH4PO4.6H2O.

However from literature and from practice, not only the optimal pH seems to be around the range from 7 to 10/11 where HPO42- is predominant as when Struvite forms tends to slightly decrease the pH of solutuon, which gives an hint for the release of a proton(H+), what suggests the real formula for struvite is
Mg2+ + NH4+ + HPO42- + 6H2O↔ MgNH4PO4.6H2O + H+.

My question is wouldn't it be more favorable for the system to generate Struvite directly from PO43- instead of HPO42-? doesn't it create a further energy consuming step for the deprotonation of the Hydrogen Phosphate?
From what I checked being pKa = 12.346 for reaction HPO42- = H+ + PO43-, the Free energy Gibbs Variation is ≅30,6 kJ mol-1, implying from what I know that this deprotonation step is not a spontaneous reaction.

Might there be a reason I'm negleting or forgetting that might explain why this reaction is driven by HPO42- instead of PO43-?

Thanks in advance for any insight you might have.
 
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I think at higher pH values, rather than NH4+, NH3 would be the predominant species in solution which is not even ionic and therefore might be more difficult to embed into the crystal lattice.
 
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I just tried to calculate the pH where the solubility of Struvite is minimal. If I got my maths right, the optimal pH is ##(\mathrm{pK_a(HPO_4^{2-})+pK_a(NH_4^{+}))/2 }##, which is about 10.9.
 
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Thank you DrDu, I was so focused on Phosphorus I didn't thought to remember the NH4+ turning to NH3 an evolving from solution.
DrDu said:
I just tried to calculate the pH where the solubility of Struvite is minimal. If I got my maths right, the optimal pH is ##(\mathrm{pK_a(HPO_4^{2-})+pK_a(NH_4^{+}))/2 }##, which is about 10.9.
That is an inteteresting value. What expression(s) did you use to get there to this sum of Pkas I don't remember this experession(maybe because I was too many years without working with solutions)?
 
I used the equations
##
K_{sp}=[Mg^{2}][NH_4^+][PO_4^{3-}] ##
## K_a(NH_4^{+})= [NH_3][H^+]/[NH_4^+]##
##K_a(HPO_4^{2-})=[PO_4^{3-}][H^+]/[HPO_4^{2-}]##
##[Mg^{2+}]=[NH_3]+[NH_4^+]=[HPO_4^{2-}]+[PO_4^{3-}]##
And looked for a minimum of ##[Mg^{2+}]## as a function of ##[H^+]##.
 
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