B Why is a black surface a better emitter of IR than a silvered surface?

AI Thread Summary
A black surface is a better emitter of infrared (IR) radiation than a silvered surface due to its ability to absorb and emit thermal radiation more effectively. This behavior aligns with the principles of blackbody radiation, where darker surfaces are known to be superior emitters and absorbers of IR compared to reflective surfaces. A silvered surface reflects IR rather than emitting it, making it less efficient as a radiator when warm. The discussion highlights the contrast between the absorption and emission capabilities of different surface finishes. Understanding these properties is essential for applications involving thermal management and energy efficiency.
Glenn G
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I can just get the idea of a silvered surface reflecting IR and a black surface absorbing IR (analogous to how light behaves) but I can't see how a silvered surface, if warm is a poorer emitter than a Matt black surface, if warm?
Would appreciate any help without going too in depth.
Regards,
G.
 
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Glenn G said:
I can just get the idea of a silvered surface reflecting IR and a black surface absorbing IR (analogous to how light behaves) but I can't see how a silvered surface, if warm is a poorer emitter than a Matt black surface, if warm?
Would appreciate any help without going too in depth.
Regards,
G.
hi there :smile:

there's no point me typing out a long answer when some one else has already done so ...

https://physics.stackexchange.com/questions/159856/why-is-black-the-best-emittercheers
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