Why is entropy of an object inversely related to its temperature?

AI Thread Summary
The discussion centers on the relationship between entropy and temperature, particularly in the context of black holes and systems with negative heat capacity. While the statement that entropy is inversely proportional to temperature is true for black holes, it does not universally apply to all systems; it is more relevant for systems like gravitationally bound gases. The conversation explores how adding energy can lead to varying effects on entropy and temperature, with examples such as steam and liquid water demonstrating different correlations. It highlights that for entropy to behave inversely with temperature, specific conditions regarding heat capacity must be met, which is not typically found in known materials. The complexities of thermodynamics and gravitational systems illustrate the fascinating interplay between energy, entropy, and temperature.
KurtLudwig
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I read in a book "Quantum Space" by Jim Baggot, page 290, that the entropy of an object is inversely proportional to its temperature. (He was describing the temperature of a black hole. Does this statement only apply to black holes?) No doubt he is correct, but wouldn't an increase of energy within an object give more possible states? Some molecules within a gas could have higher velocities. The gas might expand into a larger volume.
 
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KurtLudwig said:
Please explain why in thermodynamics the entropy (disorder) of an object is inversely related to its temperature.

In general it's not/

KurtLudwig said:
Does this statement only apply to black holes?

It's certainly a leap from "it applies to black holes" to "it applies everywhere". It is probably true for any system with negative heat capacity.
 
KurtLudwig said:
the entropy of an object is inversely proportional to its temperature

The entropy of the heat energy inside a rock is inversely proportional to the temperature of the rock. And proportional to the amount of the heat energy.

S = U/T

I wonder if we are allowed to say that the entropy of the heat energy inside a rock is inversely proportional to the temperature of the heat energy inside the rock? Like maybe the temperature T is the temperature of the heat energy U?
 
Please explain negative heat capacity.
 
KurtLudwig said:
Please explain negative heat capacity.

Do you understand heat capacity?
 
KurtLudwig said:
wouldn't an increase of energy within an object give more possible states? Some molecules within a gas could have higher velocities. The gas might expand into a larger volume.

Let's say the object is a mixture of steam and liquid water at constant pressure. When we heat this object, its heat energy increases, its entropy increases, and its temperature stays constant. And that's because when one Joule of heat energy is added to that object, the object changes so that it has one Joule more potential energy. In this case there is no correlation between temperature and entropy.

What would happen if adding one Joule of heat energy to some object caused the object to have two Joules more potential energy? Well, when that object is heated, its heat energy increases, its entropy increases, and its temperature decreases. In this case there is a negative correlation between temperature and entropy.

And there are many cases when there is a positive correlation between entropy and temperature.
 
If heat capacity ##C(T)## is a constant, entropy depends logarithmically on temperature. It's a result of integrating the infinitesimal definition

##\displaystyle dS=\frac{dQ}{T} = \frac{CdT}{T}##,

where there is the reciprocal ##T## proportionality. To get the entropy of something behave like ##S(T)\propto T^{-1}##, you'd have to set the function ##C(T)## just right for the integral to produce that result. What would it have to be?
 
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hilbert2 said:
If heat capacity ##C(T)## is a constant, entropy depends logarithmically on temperature. It's a result of integrating the infinitesimal definition

##\displaystyle dS=\frac{dQ}{T} = \frac{CdT}{T}##,

where there is the reciprocal ##T## proportionality. To get the entropy of something behave like ##S(T)\propto T^{-1}##, you'd have to set the function ##C(T)## just right for the integral to produce that result. What would it have to be?

It would have to be ##C(T)\propto-T^-1##, right? In case the entropy is positive, this would mean the heat capacity needs to be negative.
 
Livio Arshavin Leiva said:
It would have to be ##C(T)\propto-T^-1##, right? In case the entropy is positive, this would mean the heat capacity needs to be negative.

Yes, that's true and I don't think there is any material with that property.
 
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hilbert2 said:
Yes, that's true and I don't think there is any material with that property.

Every gravitationally bound system has this property.

It appears that the OP has lost interest, though.
 
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Vanadium 50 said:
Every gravitationally bound system has this property.

Like a large cloud of point particle ideal gas that doesn't expand indefinitely because gravitation holds it together? I think there's the problem of having to set both temperature and density at the exact correct values for it to not collapse either, but I don't know much about GR.
 
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While PF likes to involke GR to solve inclined plane problems, it's not necessary in this case.

A cloud of gas in space loses energy and increases temperature as it collapses. Specific heat is negative.
 
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Physics is amazing! Thanks for your analyses.
 
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