Why is gravity taken as positive?

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The discussion clarifies why gravity is treated as negative in force equations while tension is positive. When analyzing the forces acting on an elevator, the equation FT = ma + mg is derived from Newton's Second Law, where FT represents tension, m is mass, a is acceleration, and g is the acceleration due to gravity. The negative sign for gravity accounts for its downward direction, allowing the resultant force to be expressed positively. The confusion arises from the assumption that g should be negative in calculations, which is incorrect since the equation already incorporates the direction of gravity. Ultimately, the proper application of these principles ensures that the calculated tension force remains positive.
whitehorsey
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1. An elevator (mass 4700 kg) is to be designed so that the maximum acceleration is 6.80×10-2. What is the maximum force the motor should exert on the supporting cable?


Force Diagram:

Force Tension
|
elevator
|
mg


3. FT = ma + mg
4700[(0.068(-9.8) - 9.8)]
= -435178.8N
but the answer should be positive. Why isn't gravity negative?
 
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Why is it F = ma + mg? Why not F + ma = mg? Why not F + mg = ma? Why not something else?
 
voko said:
Why is it F = ma + mg? Why not F + ma = mg? Why not F + mg = ma? Why not something else?

Because the ƩF = ma
ƩF = FT - mg
So FT - mg = ma
=> FT = ma + mg
 
whitehorsey said:
Because the ƩF = ma
ƩF = FT - mg
So FT - mg = ma
=> FT = ma + mg

Then in the bolded line, acceleration due to gravity and hence weight is taken as negative whilst tension FT is taken as positive. So the resultant force ma is

ma =FT + (-mg) = FT - mg
 
Applying Newton's Second Law:
m\ddot{y}=FT-mg

g here is just +9.8. The "downward" direction of gravity is already taken care of by the minus sign in :

FT-mg

Rewriting it as
FT=m(\ddot{y}+g)
Just plug and chug...

You should get a positive tension force
 
whitehorsey said:
Because the ƩF = ma
ƩF = FT - mg
So FT - mg = ma
=> FT = ma + mg

Since that takes care of the "negative" direction of gravity, you should not further assume that g is negative like you did originally.
 
Thanks everyone!
 
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