Why is Hot Air Lighter than Cold Air?

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Hot air is lighter than cold air due to its lower density, despite having more energy and theoretically greater mass according to E=mc^2. At the same pressure, hot air expands, resulting in less mass per volume. While the molecules in hot gas may be heavier, the overall density is reduced, allowing hot air to rise above colder air. If two equal volumes of air are compared in separate vessels, the hotter air would indeed be infinitesimally heavier. This demonstrates the complex relationship between temperature, energy, and density in gases.
Skim Halo
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If E=mc^2, why is hot air lighter than cold air? Hot air has more energy and should thus have greater mass and therefore be heavier as weight = mg
 
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At the same pressure, hot air is less dense - there's less of it per volume.
Aside from that, a number of molecules on a hot gas would be heavier than the same number of the same cold gas. But it would be very hard to measure the difference. For E=mc^2, you have an awful lot of E equating to very little m.
 
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So it's the fact that the air's volume is not constrained which allows it to expand it's volume and being less dense it rises above the colder denser air.

I would assume then however that if two volumes of air were contact rained in equal sized separate vessels, the hotter air vessel would be infinitesimally heavier?
 
Skim Halo said:
I would assume then however that if two volumes of air were contact rained in equal sized separate vessels, the hotter air vessel would be infinitesimally heavier?

Exactly. Given two containers of gas, identical in all respects except for temperature, the hotter one would have a tiny bit more mass than the cooler one.
 
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