Why Is Isothermal Expansion Answer D in Homework Problems?

AI Thread Summary
Isothermal expansion is identified as answer D in homework problems because it involves heat transfer that maintains constant temperature, leading to an increase in entropy. In this process, while the internal energy remains constant, the heat added to the system during expansion results in positive entropy change. Conversely, adiabatic processes do not involve heat transfer, resulting in zero change in entropy. The discussion emphasizes that during isothermal expansion, heat flows into the system, which is essential for maintaining isothermal conditions. Thus, the reasoning behind selecting answer D is rooted in the principles of thermodynamics, particularly the second law.
Arun Raja
Messages
17
Reaction score
0

Homework Statement


http://puu.sh/c09sc/b1d02302bd.png

Homework Equations


Conceptual question.

The Attempt at a Solution


The answer is isothermal expansion(D).
but heat does not decrease due to isothermal process and expansion leads to lesser collision of particles on walls of container.
So why D?
 
Last edited by a moderator:
Physics news on Phys.org
Is not your question really, "Why not A, B, or C?

The compression processes are intuitively obvious? Adiabatic processes do not transfer heat or matter.
 
even isothermal processes occur at same temperatures. So there is no increase in internal energy which leads to increase in entropy.
 
Think of it with this equation from the 2nd law of thermodynamics:

ΔS = Q/T

For adiabatic processes, Q = 0.
For isothermal processes, entropy of the system will increase if the system is expanding because Q must be positive (heat goes into the system) for the system to remain isothermal. If the system is compressed isothermally, heat must go out of the system and entropy will decrease.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top