Why is it wrong to conclude a isn't the vertice (conics)

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Homework Help Overview

The discussion revolves around finding the equations of ellipses based on given conditions, including a focus and eccentricity. The subject area is conic sections, specifically ellipses.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the focus, directrix, and eccentricity in the context of ellipses. There is a focus on clarifying the definitions of terms such as "focus" and "vertex," and how they relate to the parameters of the ellipse.

Discussion Status

Participants are actively engaging with each other's posts, providing clarifications and corrections regarding terminology and mathematical relationships. There is an acknowledgment of misunderstandings, but no consensus has been reached on the specific approaches to solving the problems presented.

Contextual Notes

One participant notes the importance of correctly interpreting the focus and eccentricity values, while another emphasizes the need for clarity in mathematical notation. There is an indication that some information may be missing or misinterpreted in the original problem statements.

flyingpig
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Homework Statement



Given the ellipse is centered at the origin and the information, find an equation of the ellipse.

1) An ellipse with focus (\sqrt{5},0), directrix; x = \frac{9}{\sqrt{5}}

2) An ellipse with an eccentricity of 4/5




The Attempt at a Solution



I have to leave right now so I can't post a usuall good attept, but basically for #1) you cannot match the directrix with the a/e, but for #2) you are supposed to take the focus = 4
 
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flyingpig said:
but for #2) you are supposed to take the focus = 4
Hate to be picky, but a focus is a point, not a number. If
e = c/a,
where c is the distance from the center to a focus, and a is the distance from the center to a vertex (not vertice!), then you should know what a is. All it remains is for you to find b, the distance from the center to an endpoint of the minor axis, and you're done.
 
eumyang said:
Hate to be picky, but a focus is a point, not a number. If
e = c/a,
Yes, flyingpig knows that. He intended \left(\sqrt{5}, 0\right) but, for some reason had only the squareroot in LaTeX and on a separate line.

where c is the distance from the center to a focus, and a is the distance from the center to a vertex (not vertice!), then you should know what a is. All it remains is for you to find b, the distance from the center to an endpoint of the minor axis, and you're done.
Good!
 
HallsofIvy said:
Yes, flyingpig knows that. He intended \left(\sqrt{5}, 0\right) but, for some reason had only the squareroot in LaTeX and on a separate line.
Actually, I was referring to #2, where he writes:
flyingpig said:
I have to leave right now so I can't post a usuall good attept, but basically for #1) you cannot match the directrix with the a/e, but for #2) you are supposed to take the focus = 4 (emphasis mine)
 

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