Why Is My Calculation of Carnot Engine Efficiency Incorrect?

AI Thread Summary
The discussion revolves around calculating the efficiency of a Carnot engine operating between temperatures of 230°C and 120°C, with a heat absorption of 6.30*10^4 J. The efficiency formula used is eff = 1 - (Tcold/Thot), but the initial calculation yielded 47.83 percent, which was deemed incorrect. The error was identified as a failure to convert the temperatures from Celsius to Kelvin before applying the formula. Correctly converting the temperatures and recalculating will yield the accurate efficiency of the engine.
obxer22
Messages
4
Reaction score
0

Homework Statement



A Carnot engine operates between 230°C and 120°C, absorbing 6.30*10^4 J per cycle at the higher temperature.

What is the efficiency of the engine?

Homework Equations



eff = 1 - (Tcold/Thot)

The Attempt at a Solution



Using this equation, I get 47.83 percent, which the system is telling me is incorrect. Can anybody offer a solution to this? Thanks.
 
Physics news on Phys.org
i was not using kelvin, so i got the answer
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top