Why is my sensor output only 1v when using a 2.5v reference voltage?

AI Thread Summary
The sensor outputs a differential signal with a reference voltage of 2.5V, but the observed output is only 1V, indicating that the sensed variable is at an intermediate level within the sensor's range. The reference voltage is essential for proper sensor operation, likely providing power and defining the output range. The output could be influenced by factors such as a voltage divider or the specific characteristics of the sensor. To diagnose the issue accurately, the sensor's part number and additional details are necessary. Understanding the sensor's specifications and connection setup is crucial for troubleshooting the output voltage discrepancy.
rama1001
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I have sensor that produces differential output. I saw in the sensor schematic that they have used 2.5v DC as reference in the output minus terminal. I am taking sensor output as differential that both positive and negative(2.5DC ref terminal)in count. I got output as 1v of DC when the sensor is placed near to my setup(pump with Accelerometer sensor)

My doubts are..
1) What happened to 2.5 reff voltage. Why i get as 1v in output.
2) why we used these reference voltage.

Please clear my doubts.
 
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The sensor probably puts out 0-2.5V over the range of the variable sensed. Possibly, -2.5 to +2.5 V. The 1V reading means what you are sensing is intermediate in the range.

My guess is that you must supply the 2.5V for power. But it could also be a voltage divider accepting up to 2.5V. You would have to give us the part number to be sure.
 
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