Why is my two-particle wavefunction not normalizing over time?

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Homework Statement



Hi, I've been working on this for a while but I just can't seem to figure this out. I have to solve a problem regarding a one-dimensional two-particle wavefunction psi(x1, x2, t) that is normalized at t=0, and the particles are not in spin. I have to show that the wavefunction remains normalized for all time. I would appreciate any help.

The Attempt at a Solution



I know that to normalize, Integral[|psi(x1, x2, t)|^2] =1. So, I have written out the wavefunction, how I think it is, for a two particle system:

(1/a) Sin[(n*Pi*x)/(2*a)]*Sin[(m*Pi*y)/(2*a)]*Exp[-I*w*t]

Then, I went ahead and found the complex conjugate and multiplied it by the original wavefunction. I tried to integrate it on mathematica from -Infinity to Infinity, but it said the integral does not converge.
 
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Hi,

I believe that you are using the wavefuction for a particle in a box of length 2a. Hence, you don't have to integrate over all space - only in the box (i.e. from -a to a).

Having a plane wave in unbound space is unphysical and not normalisable - since that would imply that the particle exists everywhere for all time.
 
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Right. I was working it out and that's the problem I ran into. So, if that's not how it's done, how would I go about solving this problem then?
 
Actually, this problem is quite trivial if you know that wavefunction. You don't actually have to do the integral, because you can factorize e^iwt out.
 
htown1397 said:
Right. I was working it out and that's the problem I ran into. So, if that's not how it's done, how would I go about solving this problem then?

Did you read my post? You have to integrate between "a" and "-a", and NOT from infinity to -infinity.
 
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To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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