Why is the change in angle of precession equal to dL/L?

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A rapidly rotating gyroscope precesses around its perch when released horizontally, with angular momentum represented by L and a small change in momentum by dL. The relationship dA = dL/L is discussed, where dA is the change in the angle of L. The reasoning behind this is that as dL decreases, it approaches the arc length, which is directly related to the angle in radians. The use of radial coordinates clarifies that the radius is L, making the relationship valid. This explanation resolves the confusion about why dL/L corresponds to a change in angle rather than the sine of the angle.
trobinson41
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If a rapidly rotating gyroscope attached to a perch is released in a horizontal position -- that is, so that the axis of the gyroscope is horizontal -- the gyroscope will precess around it's perch. Let L represent its angular momentum. Let dL represent a small change in that momentum. Let dA represent the corresponding change in the angle of L. According to all the references I've found, dA = dL/L. I don't understand this. Shouldn't dL/L be the change in the sine of the angle, not the angle? See attached diagram. Thanks.
 

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It looks like dL and dA are both measured in radial coordinates.
dL = L * dA will give you the appropriate measure to arrive at the point L(t + dt) in the illustration. If you were to use the sine, you would be headed to a point more than |L| away from the center.
 
Your mention of radial coordinates jogged my memory. The angle in radians is the arc length / radius. The radius in this case is L. Since the arc length approaches dL as the length of dL decreases, dL/L approaches dA. I think that's the reasoning that's being used. Thanks for your help.
 
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