- #1
nickadams
- 182
- 0
Actually I changed my mind and feel like it should be ((pi*r)(2*pi*r)) by my faulty thinking.
Since pi*r would give you a line wrapped halfway around a sphere, I was thinking you could repeat this line in a radial pattern around the outside of a sphere (2*pi*r) times to get the surface area of the sphere.
That kind of logic makes sense when taking the volume of a cylinder because I imagine taking the area of the circular disk base and stacking it (height) number of times to get the volume. The meters^2 of the area and meters of the height multiply to give the m^3 of volume. So I also expected the meters of the (pi*r) and the meters of the (2*pi*r) to multiply to give me the m^2 of surface area... :/
Can someone explain in layman's terms what is wrong with this approach?
Since pi*r would give you a line wrapped halfway around a sphere, I was thinking you could repeat this line in a radial pattern around the outside of a sphere (2*pi*r) times to get the surface area of the sphere.
That kind of logic makes sense when taking the volume of a cylinder because I imagine taking the area of the circular disk base and stacking it (height) number of times to get the volume. The meters^2 of the area and meters of the height multiply to give the m^3 of volume. So I also expected the meters of the (pi*r) and the meters of the (2*pi*r) to multiply to give me the m^2 of surface area... :/
Can someone explain in layman's terms what is wrong with this approach?
Last edited: