Why is the frequency different for circuits with the same RC?

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    Circuit Inverter Time
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Discussion Overview

The discussion revolves around the differences in frequency for circuits that have the same resistance-capacitance (RC) values. Participants explore the implications of load current, voltage, and switching frequencies in relation to capacitor behavior in these circuits.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that the frequency depends on the load current or voltage that signals the end of each half cycle, providing specific values for capacitors and load.
  • Another participant calculates the time per transition based on the current and voltage, arriving at a frequency of 125kHz for the circuit described.
  • A different participant suggests that a specific formula may pertain to circuit turn-off time rather than maximum frequency, indicating uncertainty about the applicability of formulas.
  • Concerns are raised about the cost and behavior of capacitors at high switching frequencies, with a participant indicating that the circuit may be more suited for lower frequencies like 50 or 60Hz.
  • One participant questions why the frequency differs despite both circuits having the same RC, referencing a formula from an earlier post.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between load conditions and frequency, with no consensus on the correct interpretation of the formulas or the implications for circuit behavior.

Contextual Notes

There are unresolved assumptions regarding the definitions of load current and voltage, as well as the specific conditions under which the frequency is calculated. The discussion also highlights the impact of switching frequency on capacitor performance.

Who May Find This Useful

Readers interested in circuit design, particularly those dealing with RC circuits and switching frequencies, may find this discussion relevant.

jaus tail
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Homework Statement


upload_2018-1-26_16-58-22.png


Solution in Book#1
upload_2018-1-26_17-1-24.png

Solution in Google:
[/B]
upload_2018-1-26_17-1-13.png



2. Homework Equations

I don't know which solution is correct. I am struggling to remember this formula.

The Attempt at a Solution


This was a solved example so I didn't attempt.
 

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Last edited:
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It will depend on what load current or voltage is deemed to signal the end of each half cycle.
Capacitors total = 0.2uF.
H bridge current is fixed at 10A. Load = 10 ohm.
Maximum Vload = R * I = 100V.
H-bridge voltage alternates between –100 and +100, so each transition must reverse cap voltage by 200V.

Ignoring the load current and using all the current to charge and discharge the capacitors.
C = Q / V; C = I * t / V; t = C * V / I; t = 0u2F * 200V / 10A = 4u0 sec per transition.
One cycle will take 2 * 4u0 = 8u0 sec = 125kHz.
 
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I guess the In2 formula is for circuit turn off time and not for max frequency. Thanks.
 
Those capacitors are expensive when it comes to current at high switching frequencies.

It appears that this circuit would be more applicable to situations switching at power line frequencies of 50 or 60Hz, than at many tens or even hundreds of kHz. For higher frequencies, this circuit has higher currents charging and discharging the capacitors than it does through the load. After a transition, peak capacitor current can be twice the maximum load current. Total is always 10 amp but the capacitors partly discharge through the load.

Here is an idealised switching circuit simulated by LTspice. Shown clocked at 125kHz (T=8usec), and at 50kHz (T=20usec).
The three traces show total capacitor current, load current and the constant current source.

Driven at 125kHz = 8usec cycle.
Ideal_8usec.png


Driven at 50 kHz = 20usec cycle.
ideal_20usec.png
 

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Both circuits have same RC. So why is frequency different if we use your first formula in post2?
 

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