Why is the limit 2025? a simple plug and chug limit gone wrong

[mr_coffee]

Hello everyone i have the following prlbem:
lim (x,y)->(5,-2) (x^5+4x^3y-5xy^2);

So i let y be fixed at 0 and let x equal 5, and i got 5^5 which is 3125, if i let 0, and y be -2 i get 0. Doesn't this mean the limit doesn't exist? but it says its 2025, ?

 

[whozum]

Just plug in 5 for each x value and -2 for each y value, you get 2025. You were doing something completely different.

 

[mr_coffee]

ohhh i did that before and i messed up on multipcation thank u

 

[AKG]

What you're doing in your first post is like saying that if you have:

\lim _{x \to 7} x^2

and you plug in x = 3 to get 9 and plug in x = 10 to get 100, then the limit doesn't exist.