- #1
DrummingAtom
- 659
- 2
I tried deriving this one on my own and I'm just not understanding where the dx/dx term comes from. I'm looking dy/dx.
Starting with F(x,y) = 0:
[itex]\frac{\partial{F}}{\partial{x}}\frac{dx}{dx} + \frac{\partial{F}}{\partial{y}}\frac{dy}{dx} = 0[/itex]
It seems redundant to say dx/dx when it turns out to be one anyway. Why does this step need to be done? Thanks
Starting with F(x,y) = 0:
[itex]\frac{\partial{F}}{\partial{x}}\frac{dx}{dx} + \frac{\partial{F}}{\partial{y}}\frac{dy}{dx} = 0[/itex]
It seems redundant to say dx/dx when it turns out to be one anyway. Why does this step need to be done? Thanks