Why Is Voltage Not Zero at Infinity in This Electrostatic Scenario?

AI Thread Summary
In the electrostatic scenario, a point charge of -8 µC is surrounded by two conducting spherical shells, with the outer shell carrying a net charge of -8 µC. The potential at infinity is specified as 1 x 10^5 V, which is crucial for calculating the voltage at a radius of 0.1 m. The voltage difference from 0.9 m to infinity must account for the specified potential at infinity, leading to an integration that adds this value to the calculated voltage difference. The integration from 0.9 m to infinity confirms that the voltage at infinity is not zero, impacting the overall potential calculations. Understanding these relationships is essential for solving the problem accurately.
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Homework Statement



A point charge q = -8 µC is surrounded by two thick, conducting spherical shells of inner and outer radii a1 = 0.2 m, a2 = 0.3 m, a3 = 0.8 m, and a4 = 0.9 m respectively. The inner shell is uncharged; the outer shell has a net charge Q = -8 µC. At this point in the problem, the potential at infinity is unspecified. Do not assume it is zero.


If now you are given V(inf) = 1 x 105 V, find the potential at r = 0.1 m.


Homework Equations



V = ∫E*dr

The Attempt at a Solution




voltage from .1 m to .9m = -359672 + -149863 = -509535
(known from previous steps)

I have no idea how to get the voltage from .9m to infinity!
 
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hi jehan60188! :smile:

the voltage difference from .9m to infinity is the same as it would be if the voltage at infinity was 0 :wink:
 
kk, since the voltage between point A (.9 m) and B (infinity) needs to be 10^5 higher than if it were supposed to be zero, I integrate from .9 to infinity, and then add 10^5
thanks!
 
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