Why is z = rcos(θ) and not z = rsin(θ) in surface integrals?

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Miike012
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Look in the paint doc. I was wondering why they said z = rcos(θ) and not z = rsin(θ) and x = rcos(θ)
 
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The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?
 
haruspex said:
The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?

Well when i used sine I came out with a different answer but ill try again.
 
haruspex said:
The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?

You are right the answers are the same. thanks.