The OP did describe colliding beams of d's, but then asked "Doesn't the ITER do something like this?"
Well ITER is a Tokamak. And Tokamaks use neutral beam heating. They do not use accelerators, because accelearators are generally inefficient, the beam current densities are low, and the energy losses from radiation would be considerable.
I think the accelerators in HR were provably GeV or TeV range, and that's way too high when one wants d in the keV range.
I haven't seen HR or HRW, so I can't really make an accurate statement on the initial problem statement.
As for neutrons - D + D -> T + p or He
3 + n about 50/50 probability.
in D + T, the yield is He
4 + n, with the n taking 14.1 MeV of the 17.6 MeV produced.
I posted some additional information links in the thread
Q > 1 .
But these might be of more use -
http://www.iter.org/techpara.htm , where one will find
Volume-averaged ion temperature <T
i> = 8.1 keV
Volume-averaged electron temperature <T
e> = 8.9 keV
and likely D-T will be the initial fuel.
http://www.iter.org/Conditions.htm#product