I Why prompt neutron gets less share of energy (fission)

Magnetic Boy
Messages
27
Reaction score
0
why neutron get so little energy in fission reaction as compare to fission fragments?
according to formula
Em=Ef(M)/(m+M)
m=mass of small fragment
M= mass of relatively big fragment
Ef=fission energy
by the same logic neutron should get highest share due to their lower mass. i am missing something please point out. thanks
 
Physics news on Phys.org
That formula only works for decays to two particles. Fission splits the nucleus in two (rarely three) parts, those parts then emit neutrons. The decay energies of those processes are a few MeV - the energy of the prompt neutrons (to a good approximation).
 
mfb said:
That formula only works for decays to two particles. Fission splits the nucleus in two (rarely three) parts, those parts then emit neutrons. The decay energies of those processes are a few MeV - the energy of the prompt neutrons (to a good approximation).
are neutrons emit with fission simulatneously?
 
Some are clearly emitted later, for some the question becomes ambiguous - how long do you consider neutrons part of a nucleus, and when exactly is the fission process done? You don't have classical objects moving around.
 
Thread 'Why is there such a difference between the total cross-section data? (simulation vs. experiment)'
Well, I'm simulating a neutron-proton scattering phase shift. The equation that I solve numerically is the Phase function method and is $$ \frac{d}{dr}[\delta_{i+1}] = \frac{2\mu}{\hbar^2}\frac{V(r)}{k^2}\sin(kr + \delta_i)$$ ##\delta_i## is the phase shift for triplet and singlet state, ##\mu## is the reduced mass for neutron-proton, ##k=\sqrt{2\mu E_{cm}/\hbar^2}## is the wave number and ##V(r)## is the potential of interaction like Yukawa, Wood-Saxon, Square well potential, etc. I first...
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top