Why? question about optical encoder

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SUMMARY

The outermost ring of an optical encoder represents the least significant bit (LSB) due to its greater circumference, allowing for more lines to be scribed, which enhances sensor resolution. This design choice is intrinsically linked to the concept of sensor resolution rather than frequency alone. The discussion also highlights the use of Gray code in optical encoders, where the two least significant bits maintain the same frequency but are 90 degrees out of phase, a principle reminiscent of early mouse encoders.

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engineer23
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Why is the outermost ring of an optical encoder the least significant bit? Is this somehow related to frequency?
 
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There is more length in the outside ring.
For a sensor of any given resolution the wider the disk the more lines that can be scribed on it.
While in a way this relates to frequency, it is more about sensor resolution.
 
just curious, does your optical encoder use Gray code? it should. if it does, the two LSBs (of Gray code) will have the same "frequency" but will be 90o outa phase. just like the encoders of the earlier mice.
 

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