Why would his weight be zero at the moment of the fall?

AI Thread Summary
The discussion centers on the concept of "apparent weight" in the context of a person in an upward-moving elevator when the cable breaks. Participants clarify that apparent weight refers to the normal force exerted by a scale, which indicates how much weight is felt by the person. When the elevator cable is cut, both the person and the elevator enter free fall, resulting in no contact force. Consequently, the apparent weight of the person becomes zero immediately after the fall begins. This understanding highlights the relationship between apparent weight and gravitational forces during free fall.
alaa amed
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Homework Statement



A person of weight w is in an upward-moving elevator when the cable suddenly breaks. What is the person's apparent weight immediately after the elevator starts to fall?
 
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alaa amed said:

Homework Statement



A person of weight w is in an upward-moving elevator when the cable suddenly breaks. What is the person's apparent weight immediately after the elevator starts to fall?
How would you personally define the term "apparent weight?"
 
Chestermiller said:
How would you personally define the term "apparent weight?"
I think that's the key to answering the question, though I am not sure I interpreted properly. I think it means the weight relative to the force of gravity that acts on it in particular instance.
 
alaa amed said:
I think that's the key to answering the question, though I am not sure I interpreted properly. I think it means the weight relative to the force of gravity that acts on it in particular instance.
That's not correct. It means that, if he was standing on a scale, what the scale would read (i.e., the normal force the person would be exerting on the scale, and, by Newton's 3rd law, the normal force the scale would be exerting on the person). That's the definition of his apparent weight.

So, what is the normal force that the scale is exerting on the person if the elevator cable has been cut?
 
Chestermiller said:
That's not correct. It means that, if he was standing on a scale, what the scale would read (i.e., the normal force the person would be exerting on the scale, and, by Newton's 3rd law, the normal force the scale would be exerting on the person). That's the definition of his apparent weight.

So, what is the normal force that the scale is exerting on the person if the elevator cable has been cut?
I think the person and the elevator would be free falling an so there would be no contact force?
 
alaa amed said:
I think the person and the elevator would be free falling an so there would be no contact force?
Yes. That is correct. So what does that mean regarding the "apparent weight" of the person, considering the apparent weight is equal to the contact force.
 
Chestermiller said:
Yes. That is correct. So what does that mean regarding the "apparent weight" of the person, considering the apparent weight is equal to the contact force.
It will be zero! Thank you so much for your help.
I get it now.
 
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