Will 2 particles with paths crossed collide?

  • Thread starter Thread starter jefer
  • Start date Start date
  • Tags Tags
    Particles
AI Thread Summary
Two particles, A and B, are analyzed for potential collision based on their velocity vectors and starting positions. Particle A moves at 10 km/h at a 30-degree angle from the y-axis, while particle B moves at 8 km/h at a 60-degree angle from the y-axis. Calculations show that they do not collide, with a minimum distance of 1.8 km between them. The discussion emphasizes the importance of equating positions to explore collision possibilities, even if the initial assumption of collision may be incorrect. Understanding relative velocity is suggested as a key concept to clarify their motion dynamics.
jefer
Messages
2
Reaction score
0

Homework Statement


The first particle A is starting at origin and it has a velocity vector with magnitude 10km/h and moves at an angle of 30 degrees relative to y axis. The second particle B is starting at (0,5) and it has velocity vector with magnitude 8km/h and moves at an agle of 60 degrees relative to y axis. Will these 2 particles colide, and if not, what is the minimal distance they will be at?

Homework Equations


photo.php.jpg


The Attempt at a Solution


I found the velocity vectors with given angles/magnitudes. I'm not sure what to do now.
 
Physics news on Phys.org
The particles will collide at time where both at x and y displacement are equal if time t exist.
 
Yeah I got position vector rA and rB from formula r(t)=v*t, where r and v are vectors. They have this form rA=x*t*i + y*t*j where i and j are unit vectors. What do I get from equatting positions, how do I calculate time from that?

The correct answer is that they don't collide and minimal distance is 1.8km. So does it really make sense to equate postitions if we're not 100% sure they'll collide? I am really confused :/
 
Last edited:
Find time in y direction where both displacements are equal. Then on x direction or component. If both time are equal then they meet.
 
jefer,

Have you studied the concept of relative velocity? If so, what is the velocity of B relative to A?
 
jefer said:
So does it really make sense to equate positions if we're not 100% sure they'll collide? I'm really confused. :/
When trying to solve the problem, you can assume they'll collide and see what consequences arise from that assumption. If the consequences don't make sense, then you can conclude that the assumption was wrong. It's like a proof by contradiction in math, if you're familiar with those.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top