Jacobpm64
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Homework Statement
Use the box and the behavior of rational and exponential functions as [tex]x \rightarrow \infty[/tex] to predict whether the integrals converge or diverge.
Here is the box:
[tex]\int^\infty_1 \frac{1}{x^p} dx[/tex] converges for p > 1 and diverges for p < 1.
[tex]\int^1_0 \frac{1}{x^p} dx[/tex] converges for p < 1 and diverges for p > 1.
[tex]\int^\infty_0 e^{-ax} dx[/tex] converges for a > 0.
Problem 1:
[tex]\int^\infty_1 \frac{x^2}{x^4 + 1} dx[/tex]
Problem 2:
[tex]\int^\infty_1 \frac{x^2 - 6x + 1}{x^2 + 4} dx[/tex]
Homework Equations
The ones in the box above.
The Attempt at a Solution
Problem 1:
I know that this integral is less than [tex]\int^\infty_1 \frac{1}{x} dx[/tex]. I also know that [tex]\int^\infty_1 \frac{1}{x} dx[/tex] diverges. This does not help me though because I can not use a diverging integral to say that a smaller integral is also diverging. This is where I'm confused.
Problem 2:
I know that this integral is less than [tex]\int^\infty_1 1 dx[/tex] I also know that [tex]\int^\infty_1 1 dx[/tex] diverges. This does not help me though because I can not use a diverging integral to say that a smaller integral is also diverging. So, I'm confused at the same place on this problem.