Winning at KENO: Calculating the Expected Value (E(n))

AI Thread Summary
The discussion focuses on calculating the expected value (E(n)) in Keno, specifically addressing the formula E(n) = Ʃ p(n) × a(n), where p(n) represents the probability of getting i matches and a(n) denotes the winnings for i matches. Participants express confusion about the specific values for a(20), a(21), and the overall calculation for E(40). There is a consensus that the question lacks sufficient data, particularly regarding the number of chosen numbers and their matches. Additionally, it is suggested that E(40) likely refers to the expected winnings for a 40-number selection rather than the probability of achieving 40 matches. The conversation emphasizes the need for clarity in the problem's parameters to accurately compute expected values in Keno.
sam_0017
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game of KENO ?

can anyone help whit this question ?

[PLAIN]http://up.arab-x.com/Oct11/doY59204.png


E(n) = Ʃ p(n) × a(n)
" represent the probability you get i matches as P(i), the amount you win for i
matches as A(i) and the expected value for n numbers picked as E(n)."
 
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sam_0017 said:
can anyone help whit this question ?

E(n) = Ʃ p(n) × a(n)
" represent the probability you get i matches as P(i), the amount you win for i
matches as A(i) and the expected value for n numbers picked as E(n)."

E(40)? what's a(20) , a(21), etc. ? also i think the question is not complete , given data is not sufficient (for eg. with what (and how many ) numbers the chosen numbers are matched )
 
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I'm assuming for the moment that you know how to calculate the probabilities for the numbers of matches. I suspect what the author is calling "E(40)" is the expected value of your winnings for this 40-choice version of the game, not the probability of up to 40 matches (which happens only a little sooner than the heat-death of the Universe... ;) ). Is it the case that the other problem (which I'm guessing is related to basic Keno) asks for "E(20)" ?
 
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